If you’ve worked with APIs you’ve probably gotten this error and know how annoying it is. All because the native function never returns any actionable error for its request timing out. The best way to detect if the fsockopen() function request is timing out is to use a error control operator. The idea is to suppress the timeout warning with a @ prefix, so the function only returns true if it completes its cycle/request. You can review the example PHP code below.
if($fp = @fsockopen($host, $port, $errno, $errstr, $timeout)) {
return true;
}else{
return false;
}
Issues? leave your questions.
Published by
Miguel
I am a bilingual Network Engineer with over 20 years of professional experience in computer science and information technology. I am the founder and operator of Web Semantics, based in Vancouver, Washington, where I design, secure, and manage enterprise-grade infrastructure for small and mid-sized businesses across the West Coast. I provide bilingual IT support in English and Spanish, specializing in network architecture, systems engineering, security, and operational resilience.
Soy un ingeniero de redes bilingüe con más de 20 años de experiencia profesional en ciencias de la computación y tecnología de la información. Soy fundador y operador de Web Semantics, con sede en Vancouver, Washington, donde diseño, protejo y administro infraestructura empresarial para pequeñas y medianas empresas en la costa oeste. Ofrezco soporte de IT bilingüe en inglés y español, con especialización en arquitectura de redes, ingeniería de sistemas, seguridad y resiliencia operativa.View all posts by Miguel
